(t)=-16t^2+318

Solution for (t)=-16t^2+318 equation:

(t)=-16t^2+318

We move all terms to the left:

(t)-(-16t^2+318)=0

We get rid of parentheses

16t^2+t-318=0

a = 16; b = 1; c = -318;
Δ = b2-4ac
Δ = 12-4·16·(-318)
Δ = 20353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{20353}}{2*16}=\frac{-1-\sqrt{20353}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{20353}}{2*16}=\frac{-1+\sqrt{20353}}{32}
$